The area of the region bounded by the cu...

The area of the region bounded by the curve `y = (1)/(1 + (tan x)^(sqrt(2))` and the x-axis between the ordinates `x = pi//6` and `x = pi//3` is

A

`pi//4`

B

`pi//2`

C

`pi//8`

D

none of these

Verified by Experts

The correct Answer is:

D

Similar Questions

Explore conceptually related problems

The area of the region bounded by the curve y = |x - 1| and y = 1 is:

The area of the region bounded by the curves y=|x-1|andy=3-|x| is

The area of the region bounded by the curve y=sqrt(16-x^(2)) and X-axis is

The area bounded by the curve y = (x - 1)^(2) , y = (x + 1)^(2) and the x -axis is

The area of the region bounded by the curve y = x + 1 and the lines x=2, x=3, is

The area of the region bounded by the curve y=x^(3) , X-axis and the ordinates x = 1, x = 4 is

The area bounded by the curve y=(x-1)(x-2)(x-3) and x -axis lying between the ordinates x = 0 and x = 4 is

The area of the region bounded by the curve y="sin"2x, y-axis and y=1 is :

The area of the region bounded by the curve y=x"sin"x, x-axis, x=0 and x=2pi is :

Find the area of the region bounded by the curve y = sin x between x = 0 and x= 2pi .