Find the point P on the parabola y^2 = 4...

Find the point P on the parabola `y^2 = 4ax` such that area bounded by the parabola, the x-axis and the tangent at P is equal to that of bounded by the parabola, the x-axis and the normal at P.

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The correct Answer is:

`(3a, 2a sqrt(3)` and `(3a, - 2a sqrt(3))`

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