Let f(x)="max"{sin x,cos x,1/2}, then de...

Let `f(x)="max"{sin x,cos x,1/2}`, then determine the area of region bounded by the curves `y=f(x)`, X-axis, Y-axis and `x=2pi`.

Verified by Experts

The correct Answer is:

`((5 pi)/(12) + sqrt(2) + sqrt(3))` sq. units

Similar Questions

Explore conceptually related problems

If f(x) = max {sin x, cos x,1/2}, then the area of the region bounded by the curves y =f(x), x-axis, Y-axis and x=(5pi)/3 is

Find the area of that region bounded by the curve y="cos"x, X-axis, x=0 and x=pi .

The area of the region bounded by the curve y=x"sin"x, x-axis, x=0 and x=2pi is :

The area of the region bounded by the curve y= 2x -x^(2) and x - axis is

The area of the region bounded by the curve y="sin"2x, y-axis and y=1 is :

The area of the region bounded by the curve y=sqrt(16-x^(2)) and X-axis is

Find the area of the region bounded by the curve y=|x+1| , lines x= -4,x=2 and X-axis.

Find the area of the region bounded by the curve y = sin x between x = 0 and x= 2pi .

The area bounded by the curve y=4-x^(2) and X-axis is

Find the area of region bounded by the curve a y^2=x^3, the y-axis and the lines y=a and y=2adot