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Each of 10 passengers board any of th...

Each of 10 passengers board any of the three buses randomly which has no passenger initially. The probability that each bus has got at least one passenger, is : `(^(10)P_3 .3^7)/(3^(10))` (b) `(^(10)C_3 .3^7)/(3^(10))` `1-(2^(10))/(3^(10))` (d) `(3^(10)-3. 2^(10)+3)/(3^(10))`

Text Solution

Verified by Experts

The correct Answer is:
`3^(10)-.^(3)C_(1)2^(10)+.^(3)C_(2)1^(10)`
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