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If orthocentre of the triangle formed by...

If orthocentre of the triangle formed by `ax^2+2hxy+by^2= 0 and px + qy =1 ` is (r,s) then prove that `r/p=s/q=(a+b)/(aq^2+bq^2-2hpq)`

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The correct Answer is:
`(a+b)/(aq^2-2hpq+bq^2)`
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