find the equation of the straight line which passes through the point `(3,2)` and whose gradient is 3.

Answer

To find the equation of the straight line that passes through the point (3, 2) and has a gradient (slope) of 3, we can use the point-slope form of the equation of a line. The point-slope form is given by:

\[ y - y_1 = m(x - x_1) \]

Where:
- \( (x_1, y_1) \) is a point on the line,
- \( m \) is the gradient (slope) of the line.

### Step 1: Identify the given values
Here, we have:
- \( x_1 = 3 \)
- \( y_1 = 2 \)
- \( m = 3 \)

### Step 2: Substitute the values into the point-slope form
Substituting the values into the equation:

\[ y - 2 = 3(x - 3) \]

### Step 3: Simplify the equation
Now, we will simplify the equation:

1. Distribute the 3 on the right side:
\[ y - 2 = 3x - 9 \]

2. Add 2 to both sides to isolate \( y \):
\[ y = 3x - 9 + 2 \]

3. Combine like terms:
\[ y = 3x - 7 \]

### Final Equation
Thus, the equation of the straight line is:

\[ y = 3x - 7 \]

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