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h(x)=3f((x^2)/3)+f(3-x^2)AAx in (-3, 4) ...

`h(x)=3f((x^2)/3)+f(3-x^2)AAx in (-3, 4)` where `f''(x)> 0 AA x in (-3,4),` then `h(x)` is

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The correct Answer is:
h(x) is decreasing in `-3/2 lt x lt 3/2` , and h(x) is increasing `-3 lt x lt 3/2 and 3/2 lt x lt 4`.
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