Find the equations of the tangents dr...

Find the equations of the tangents drawn to the curve `y^2-2x^3-4y+8=0` from the point `(1,\ 2)` .

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The correct Answer is:

`y-2sqrt3x+2(sqrt3-1)=0 and y +2sqrt3x -2(sqrt3 +1) = 0`

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