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If l=int((2x-3)^(1/2))/((2x-3)^(1/3)+1)d...

If `l=int((2x-3)^(1/2))/((2x-3)^(1/3)+1)dx=3[(1)/(7)(2x-3)^(7/6)-(1)/(5)(2x-3)^(5/6)+(1)/(3)(2x-3)^(1/2)-(2x-3)^(1/6)+g(x)]+c` then g(x) is equal to

A

`tan^(-1)(2x-3)^(1//6)`

B

`(2x-3)^(1//2)`

C

`3tan^(-1)(2x-3)^(1//6)`

D

`4(2x-3)^(1//6)`

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