The axix of the parabola `9y^(2)-16x-12y-57=0` is

The axis of the parabola 9y^2-16x-12y-57 = 0 is

Find the axis, tangent at the vertex, vertex, focus, directrix and latus rectum of the parabola 9y^2 - 16x-12y-57=0

The vertex of the parabola y^(2) - 4y - 16 x - 12 = 0 is

The vertex of the parabola : 4y^(2)+12x-20y+67=0 is :

The directrix of the parabola x^2-4x-8y + 12=0 is

The directrix of the parabola x^2-4x-8y + 12=0 is

The directrix of the parabola x^2-4x-8y + 12=0 is

The length of the latus rectum of the parabola 4y^(2)+12x-20y+67=0 is

The vertex of the parabola x^(2)+12x-9y=0 is

The vertex of the parabola (y-2)^2=16(x-1) is a. (1,2) b. (-1,2) c. (1,-2) d. (2,1)