The radius of the circle touching the parabola `y^(2)=x` at (1,1) and having the directrix of `y^(2)=x` as its normal is

The radius of circle, touching the parabola y^(2)=8x at (2, 4) and passing through (0, 4), is

The equation to the normal to the parabola y^(2)=4x at (1,2) is

The equation to the normal to the parabola x^(2) = 2y at (1, 2) is

The radius of the circle touching the line x+y=4" at "(1, 3) and intersecting x^(2)+y^(2)=4 orthogonally is

The equation of the directrix of the parabola x^(2) = 8y is

The equation of the circle, which touches the parabola y^2=4x at (1,2) and passes through the origin is :

The equation of the chord of the parabola y^(2)=2x having (1,1) as its midpoint is

Find the equation of the parabola with vertex is at (2,1) and the directrix is x=y-1.

The equation (s) of circle (s) touching 12x - 5y = 7 at (1, 1) and having radius 13 is/are

The area (in sq. units) of the smaller of the two circles that touch the parabola, y^(2) = 4x at the point (1, 2) and the x-axis is: