The normal chord at a point \'t\' on the...

The normal chord at a point `\'t\'` on the parabola `16y^2 = x` subtends a right angle at the vertex. Then `\'t\'` is equal to (A) `-sqrt(2)` (B) `2` (C) `1/64` (D) none of these

A

`sqrt3`

B

`sqrt2`

C

`-sqrt3`

D

`-sqrt2`

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The correct Answer is:

B, D

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