Prove that the normal chord to a parabola `y^2=4ax` at the point whose ordinate is equal to abscissa subtends a right angle at the focus.

Prove that the normal chord to a parabola at the point whose ordinate is equal to the abscissa subtends a right angle at the focus.

Prove that the normal chord to a parabola at the point whose ordinate is equal to the abscissa subtends a right angle at the focus.

Equation of normal to y^(2) = 4x at the point whose ordinate is 4 is

The normal to parabola y^(2) =4ax from the point (5a, -2a) are

The normal chord of a parabola y^2= 4ax at the point P(x_1, x_1) subtends a right angle at the

Length of the shortest normal chord of the parabola y^2=4ax is

Find the equation of the normal to the parabola y^2 = 4ax such that the chord intercepted upon it by the curve subtends a right angle at the verted.

The point of intersection of normals to the parabola y^(2) = 4x at the points whose ordinates are 4 and 6 is

The co-ordinates of a point on the parabola y^(2)=8x whose ordinate is twice of abscissa, is :

For the parabola y^(2)=4ax, the ratio of the subtangent to the abscissa, is