Home
Class 12
MATHS
Find the locus of the point of intersect...

Find the locus of the point of intersection of perpendicular tangents to the circle `x^(2) + y^(2)= 4`

Text Solution

Verified by Experts

The correct Answer is:
`a(x^(2) - 25) = 2xy `
Promotional Banner

Similar Questions

Explore conceptually related problems

Find the locus of the point of intersections of perpendicular tangents to the circle x^(2) +y^(2) =a^(2)

Locus of the point of intersection of perpendicular tangents to the circles x^(2)+y^(2)=10 is

The locus of the point of intersection of perpendicular tangents to the circles x^(2)+y^(2)=a^(2) and x^(2)+y^(2)=b^(2) , is

Locus of point of intersection of perpendicular tangents to the circle x^(2)+y^(2)-4x-6y-1=0 is

The locus of the point of intersection of the perpendicular tangents to the circle x^(2)+y^(2)=a^(2), x^(2)+y^(2)=b" is "

The locus of the point of intersection of the perpendicular tangents to the ellipse 2x^(2)+3y^(2)=6 is

STATEMENT-1 : The agnle between the tangents drawn from the point (6, 8) to the circle x^(2) + y^(2) = 50 is 90^(@) . and STATEMENT-2 : The locus of point of intersection of perpendicular tangents to the circle x^(2) + y^(2) = r^(2) is x^(2) + y^(2) = 2r^(2) .

The locus of the point of intersection of perpendicular tangents to the parabola y^(2)=4ax is

Find the locus of the point of intersection of the perpendicular tangents of the curve y^2+4y-6x-2=0 .

Find the locus of the point of intersection of the perpendicular tangents of the curve y^2+4y-6x-2=0 .