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Find the equation of hyperbola whose ecc...

Find the equation of hyperbola whose eccentricity is `5//4` , whose focus is `(3, 0)` and whose directrix is `4x - 3y = 3`.

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To find the equation of the hyperbola with the given parameters, we can follow these steps: ### Step 1: Identify the Given Information We are given: - Eccentricity \( e = \frac{5}{4} \) - Focus \( F(3, 0) \) - Directrix \( 4x - 3y = 3 \) ### Step 2: Find the Distance from the Focus to a Point on the Hyperbola Let \( P(x, y) \) be a point on the hyperbola. The distance from the point \( P \) to the focus \( F(3, 0) \) is given by: \[ d_F = \sqrt{(x - 3)^2 + y^2} \] ### Step 3: Find the Distance from the Point to the Directrix The distance from the point \( P(x, y) \) to the directrix \( 4x - 3y - 3 = 0 \) can be calculated using the formula for the distance from a point to a line: \[ d_D = \frac{|4x - 3y - 3|}{\sqrt{4^2 + (-3)^2}} = \frac{|4x - 3y - 3|}{5} \] ### Step 4: Set Up the Relationship Using Eccentricity For a hyperbola, the relationship between the distances is given by: \[ d_F = e \cdot d_D \] Substituting the values we have: \[ \sqrt{(x - 3)^2 + y^2} = \frac{5}{4} \cdot \frac{|4x - 3y - 3|}{5} \] This simplifies to: \[ \sqrt{(x - 3)^2 + y^2} = \frac{1}{4} |4x - 3y - 3| \] ### Step 5: Square Both Sides Squaring both sides to eliminate the square root gives: \[ (x - 3)^2 + y^2 = \left(\frac{1}{4} (4x - 3y - 3)\right)^2 \] Expanding both sides: \[ (x - 3)^2 + y^2 = \frac{1}{16} (4x - 3y - 3)^2 \] ### Step 6: Expand and Simplify Expanding the left side: \[ (x^2 - 6x + 9 + y^2) = \frac{1}{16} (16x^2 - 24xy + 9y^2 - 24x + 24y + 9) \] Multiply through by 16 to eliminate the fraction: \[ 16(x^2 - 6x + 9 + y^2) = 16x^2 - 24xy + 9y^2 - 24x + 24y + 9 \] ### Step 7: Rearranging the Equation Rearranging gives: \[ 16x^2 - 96x + 144 + 16y^2 = 16x^2 - 24xy + 9y^2 - 24x + 24y + 9 \] Cancelling \( 16x^2 \) from both sides: \[ -96x + 144 + 16y^2 = -24xy + 9y^2 - 24x + 24y + 9 \] Rearranging further: \[ 24xy + 7y^2 - 72x + 135 = 0 \] ### Final Equation of the Hyperbola Thus, the equation of the hyperbola is: \[ 24xy + 7y^2 - 72x + 135 = 0 \]
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