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If the ratio of transverse and conjugate...

If the ratio of transverse and conjugate axis of the hyperbola `x^2 / a^2 - y^2 / b^2 = 1` passing through the point `(1, 1)` is `1/3`, then its equation is

A

`9x^(2) - y^(2) = 9 `

B

`x^(2) - 9y^(2) = 8 `

C

`9x^(2) - y^(2) = 8 `

D

`x^(2) - 9y^(2) = 9 `

Text Solution

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The correct Answer is:
To solve the problem, we need to find the equation of the hyperbola given the conditions. Let's break it down step by step. ### Step 1: Understand the given hyperbola equation The standard form of the hyperbola is given by: \[ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \] where \(2a\) is the length of the transverse axis and \(2b\) is the length of the conjugate axis. ### Step 2: Use the ratio of the axes We are given that the ratio of the transverse axis to the conjugate axis is \( \frac{1}{3} \). Therefore, we can write: \[ \frac{2a}{2b} = \frac{1}{3} \] This simplifies to: \[ \frac{a}{b} = \frac{1}{3} \] From this, we can express \(b\) in terms of \(a\): \[ b = 3a \] ### Step 3: Substitute the point into the hyperbola equation The hyperbola passes through the point \((1, 1)\). We substitute \(x = 1\) and \(y = 1\) into the hyperbola equation: \[ \frac{1^2}{a^2} - \frac{1^2}{b^2} = 1 \] This simplifies to: \[ \frac{1}{a^2} - \frac{1}{b^2} = 1 \] ### Step 4: Substitute \(b\) in terms of \(a\) Now we substitute \(b = 3a\) into the equation: \[ \frac{1}{a^2} - \frac{1}{(3a)^2} = 1 \] This becomes: \[ \frac{1}{a^2} - \frac{1}{9a^2} = 1 \] Finding a common denominator, we have: \[ \frac{9 - 1}{9a^2} = 1 \] which simplifies to: \[ \frac{8}{9a^2} = 1 \] ### Step 5: Solve for \(a^2\) Cross-multiplying gives: \[ 8 = 9a^2 \] Thus, we find: \[ a^2 = \frac{8}{9} \] ### Step 6: Find \(b^2\) Now we can find \(b^2\) using \(b = 3a\): \[ b^2 = (3a)^2 = 9a^2 = 9 \cdot \frac{8}{9} = 8 \] ### Step 7: Write the equation of the hyperbola Now we substitute \(a^2\) and \(b^2\) back into the hyperbola equation: \[ \frac{x^2}{\frac{8}{9}} - \frac{y^2}{8} = 1 \] Multiplying through by \(72\) (the least common multiple of the denominators) to eliminate the fractions: \[ 9x^2 - 9y^2 = 72 \] Rearranging gives: \[ 9x^2 - y^2 = 72 \] ### Final Step: Simplify the equation The final equation of the hyperbola is: \[ 9x^2 - y^2 = 72 \]
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