If `cot^(-1)(n/(pi))lt(pi)/(6),ninN` then find the minimum value of n

If cot^(-1)(n/(pi))>(pi)/6, n in N , then the maximum value of n is :

If cot^(-1)(n/(pi))>(pi)/6, n in N , then the maximum value of n is :

If cos^(-1)((n)/(2pi))lt(2pi)/(3) then maximum and minimum values of integer in are respectively

If cos^(-1)((n)/(2pi)) gt(2pi)/(3) then maximum and minimum values of integer n are respectively

If cos^(-1)(n)/(2pi)gt(2pi)/(3) then maximum and minimum values of integer in are respectively

If cot^(-1)n/pi>pi/6,n in N , then the maximum value of n is 6 (b) 7 (c) 5 (d) none of these

If f(theta)=sum_(n=1)^(6)cos ec(theta+((n-1)pi)/(4))cos ec(theta+(npi)/(4)) , where 0ltthetalt(pi)/(2) , then find the minimum value of f(theta) .

If cot^(-1)((n^2-10 n+21. 6)/pi)>pi/6, then the possible values of n is/are (a) 3 (b) 2 (c) 4 (d) 8

If-(pi)/(2)lt0lt(pi)/(2), then the minimum value of cos^(3)theta+sec^(3)thets is

If equation sin^(-1) (4 sin^(2)theta + sin theta) + cos^(-1) (6 sin theta - 1) = (pi)/(2) has 10 solution for theta in [0, n pi] , then find the minimum value of n