The number of ordered pairs which satisf...

The number of ordered pairs which satisfy the equation `x^2+2xsin(x y)+1=0` are (where `y in [0,2pi]` ) (a) 1 (b) 2 (c) 3 (d) 0

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The correct Answer is:

`x=pm1 y=2bpi-(pi)/(2)`

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