Show that vectors `|barb|bara+|bara|barb and |barb||bara-|bara|b` are orthogonal.

If theta is the angle between any two vectors bara and barb and | bara xx barb | = | bara.barb | , then value of theta is

If barc=bara times barb and barb=barc times bara then

For three non-coplanar vectors bara,barb,barc the relation |(bara times barb).barc|=|bara||barb||barc| holds true , if

For any three vectors bara, barb, barc prove : [bara-barb, barb-barc, barc-bara]=0

Prove that [bara times barb bara times barc bard]=(bara.bar d)[bara barb barc]

The position vector of the point which divides the join of points with position vectors bara+barb and 2 bara - barb in the ratio 1:2 is

Given vectors barCB=bara, barCA=barb and barCO=barx where O is the centre of circle circumscribed about DeltaABC , then find vector barx

bara,barb,barc are three unit vectors such that |bara-barb|^2+|bara-barc|^2=8 ,then |bara+2barb|^2+|bara+2barc|^2=

IF barx times barb=barc times barb and barx . bara =0 then barx=

For any two vectors barA and barB if barA.barB=|bar AxxbarB| , the magnitude of barC=barA+barB is equal to :