Let `vecu and vecv` be unit vectors such that `vecu xx vecv + vecu = vecw and vecw xx vecu = vecv` . Find the value of `[vecu vecv vecw ] `

Let vecu, vecv and vecw be three unit vectors such that vecu + vecv + vecw = veca, vecuxx (vecv xx vecw)= vecb, (vecu xx vecv) xx vecw= vecc, vec a.vecu=3//2, veca.vecv=7//4 and |veca|=2 Vector vecu is

Let vecu,vecv and vecw be vectors such that vecu+ vecv + vecw =0 if |vecu|= 3, |vecv|=4 and |vecw|=5 then vecu.vecv + vecv .vecw + vecw .vecu is (a) 47 (b) -25 (c) 0 (d) 25

Let vecu,vecv and vecw be vectors such that vecu+ vecv + vecw =0 if |vecu|= 3, |vecv|=4 and |vecw|=5 then vecu.vecv + vecv .vecw + vecw .vecu is

Let vecu,vecv and vecw be vectors such that vecu+ vecv + vecw =0 if |vecu|= 3, |vecv|=4 and |vecw|=5 then vecu.vecv + vecv .vecw + vecw .vecu is

If u and v are two non-collinear unit vectors such that |vecu × vecv| = ∣ ​ (vecu − vecv) /2 ​ ∣ ​ , then the value of ∣ vecu ×( vecu × vecv) ∣ ^2 is equal to

Let vecu and vecv be unit vectors. If vecw is a vector such that vecw+vecwxxvecu=vecv , then prove that |(vecuxxvecv).vecw|le1/2 and that the equality holds if and only if vecu is perpendicular to vecv .

If vecu,vecv and vecw are vectors such that vecu+vecv+vecw=vec0 then [vecu+vecv vecv+vecw vecw+vecu])= (A) 1 (B) [vecu vecv vecw] (C) 0 (D) -1

If vecu, vecv, vecw are three vectors such that [vecu vecv vecw]=1 , then 3[vecu vecv vecw]-[vecv vecw vecu]-2[vecw vecv vecu]=

Let vecu, vecv, vecw be three unit vectors such that vecu+vecv+vecw=veca,veca.vecu=3/2, veca.vecv=7/4 |veca|=2, then (A) vecu.vecv=3/2 (B) vecu.vecw=0 (C) vecu.vecw=-1/4 (D) none of these

If vecu and vecv be unit vectors. If vecw is a vector such that vecw+(vecwxxvecu)=vecv then vecu.(vecvxxvecw) will be equal to