Given that `veca` is a perpendicular to `vecb` and p is a non zero scalar, solve for `barr` when `p vecr+(vecr.vecb)veca=vecc`.

If veca is perpendicular to vecb and vecr is a non-zero vector such that pvecr + (vecr.vecb)veca=vecc , then vecr is:

If veca and vecb be two non collinear vectors such that veca=vecc+vecd , where vecc is parallel to vecb and vecd is perpendicular to vecb obtain expression for vecc and vecd in terms of veca and vecb as: vecd= veca- ((veca.vecb)vecb)/b^2,vecc= ((veca.vecb)vecb)/b^2

Given vec(a) is perpendicular to vecb+vecc , vecb is perpendicular to vecc+veca and vecc is perpendicular to veca+vecb . If |veca|=1, |vecb|=2, |vecc|=3 , find |veca+vecb+vecc|

If veca and vecb are two given vectors and k is any scalar,then find the vector vecr satisfying vecr xx veca +k vecr=vecb .

If veca, vecb, vecc non-zero vectors such that veca is perpendicular to vecb and vecc and |veca|=1, |vecb|=2, |vecc|=1, vecb.vecc=1 . There is a non-zero vector coplanar with veca+vecb and 2vecb-vecc and vecd.veca=1 , then the minimum value of |vecd| is

Find vecr such that tvecr+vecr+veca=vecb .

If veca and vecb are mutually perpendicular unit vectors, vecr is a vector satisfying vecr.veca =0, vecr.vecb=1 and (vecr veca vecb)=1 , then vecr is:

If vecb is not perpendicular to vecc . Then find the vector vecr satisfying the equation vecr xx vecb = veca xx vecb and vecr. vecc=0

If vecb is not perpendicular to vecc . Then find the vector vecr satisfying the equation vecr xx vecb = veca xx vecb and vecr. vecc=0

If veca, vecb and vecc are vectors such that |veca|=3,|vecb|=4 and |vecc|=5 and (veca+vecb) is perpendicular to vecc,(vecb+vecc) is perpendicular to veca and (vecc+veca) is perpendicular to vecb then |veca+vecb+vecc|= (A) 4sqrt(3) (B) 5sqrt(2) (C) 2 (D) 12