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phati+3hatj+4hatk and sqrt(q)i+4hatk are...

`phati+3hatj+4hatk and sqrt(q)i+4hatk` are two vectors, where `p,q ge 0` are two scalars, the length of the vectors are equal then

A

all values of (p,q)

B

only finite number of values of (p,q)

C

infinite number of values (p,q)

D

no value of (p,q)

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the values of the scalars \( p \) and \( q \) such that the lengths (magnitudes) of the two given vectors are equal. ### Step 1: Define the vectors Let vector \( \mathbf{a} = p \hat{i} + 3 \hat{j} + 4 \hat{k} \) and vector \( \mathbf{b} = \sqrt{q} \hat{i} + 4 \hat{k} \). ### Step 2: Calculate the magnitudes of the vectors The magnitude of vector \( \mathbf{a} \) is given by: \[ |\mathbf{a}| = \sqrt{p^2 + 3^2 + 4^2} = \sqrt{p^2 + 9 + 16} = \sqrt{p^2 + 25} \] The magnitude of vector \( \mathbf{b} \) is given by: \[ |\mathbf{b}| = \sqrt{(\sqrt{q})^2 + 0^2 + 4^2} = \sqrt{q + 16} \] ### Step 3: Set the magnitudes equal Since the lengths of the vectors are equal, we have: \[ |\mathbf{a}| = |\mathbf{b}| \] This leads to the equation: \[ \sqrt{p^2 + 25} = \sqrt{q + 16} \] ### Step 4: Square both sides to eliminate the square roots Squaring both sides gives: \[ p^2 + 25 = q + 16 \] ### Step 5: Rearrange the equation Rearranging the equation results in: \[ p^2 - q + 9 = 0 \] This can be rewritten as: \[ q = p^2 + 9 \] ### Step 6: Analyze the conditions for \( p \) and \( q \) Since \( p \) and \( q \) are scalars that must be non-negative (\( p, q \geq 0 \)), we analyze the equation \( q = p^2 + 9 \): - The minimum value of \( p^2 \) is \( 0 \) (when \( p = 0 \)), which gives \( q = 9 \). - As \( p \) increases, \( q \) also increases without bound. ### Step 7: Conclusion Thus, we find that: - \( q \) must be greater than or equal to \( 9 \) (i.e., \( q \geq 9 \)). - There are infinite pairs of \( (p, q) \) that satisfy the equation since for every non-negative value of \( p \), there is a corresponding value of \( q \). ### Final Answer The values of \( p \) and \( q \) can take infinitely many pairs such that \( q = p^2 + 9 \) with the condition \( q \geq 9 \).
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