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Potential in the x-y plane is given as V...

Potential in the x-y plane is given as `V=5(x^(2)+xy)` volts. Find the electric field at the point (1, -2).

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To find the electric field at the point (1, -2) given the potential \( V = 5(x^2 + xy) \) volts, we will follow these steps: ### Step 1: Understand the relationship between electric field and potential The electric field \( \vec{E} \) is related to the electric potential \( V \) by the equation: \[ \vec{E} = -\nabla V \] where \( \nabla V \) is the gradient of the potential. ...
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