A uniform electric field of intensity `E = 10^(6) V//m` exist in vertically downwards direction in a region. A particle of mass m = 0.01 kg and charge `q= 10^(-6) C` is suspended byan inextensible thread of length `I= 1m`. The particle is displaced slightly from its mean position and released. Calculate the time period of its oscillation. What minimum velocity should be given to the particle at rest from its equilibrium position so that it completes a full circle in vertical plane? Calculate the maximum and minimum tension in the thread in its circular motion in vertical plane. `[0.6s, 23.42 m//s, 6.59 N,0]`

Explanation

To solve the problem step by step, we will break it down into parts as follows:

### Step 1: Calculate the effective gravitational field (g effective)
The effective gravitational field is the sum of the gravitational acceleration (g) and the acceleration due to the electric field (E).

1. **Given:**
- Electric field intensity, \( E = 10^6 \, \text{V/m} \)
- Charge of the particle, \( q = 10^{-6} \, \text{C} \)
...