Home
Class 12
PHYSICS
A charged cork ball having mass of 1 gra...

A charged cork ball having mass of 1 gram and charge q is suspended on a light string in a uniform electric field as shown in the figure. The ball is in equilibrium at `0=37^(@)`, when value of electric field is `vecE=(3hati+5hatj)xx10^(5)N//C`. Assume T as tension in the string. Which of the following options are correct? (Given `sin37^(@)=0.60andg=10m//s^(2)`)

A

`q=11xx10^(-9)C`

B

`T=5.55xx10^(-3)N`

C

`q=12xx10^(9)C`

D

`T=4.55xx10^(-3)N`

Text Solution

Verified by Experts

The correct Answer is:
A, B
Promotional Banner

Similar Questions

Explore conceptually related problems

A charged cork ball of mass m is suspended on a light sting in the presence of a uniform electric field as shown in fig. When E=(A hat i+B hat j)NC^(-1) , Where A and B positive numbers, the ball is in equilibirum at theta . Find (a) the charge on the ball and (b) the tension in the string.

A charged ball of mass 9 kg is suspended from a string in a uniform elelctric field vecE = (3hati + 5hatj) xx 10^5 N//C . The ball is in equilibrium with theta=37^@ . If direction of electric field is reversed, find the new equilibrium position of the ball. Given your answer in terms of angle made by string with vertical. Take g = 10ms^(-2) .

A charged cork of mass m suspended by a light string is placed in uniform electric field filed of strength E = (hati+hatj) xx 10^(5)NC^(-1) as shown in the figure. If in equilibrium position tension in the string is 2mg//(1+sqrt3) the angle alpha with the vertical can be

A charged oil drop weighing 1.6 xx 10^(-15) N is found to remain suspended in a uniform electric field of intensity 2 xx 10^3NC^(-1) . Find the charge on the drop.

A water particle of mass 10.0 mg and having a charge of 1.50 xx 10^(-6)C stays suspended in a room. What is the magnitude of electric field in the room ? What is its direction?

A 0.50 gm ball carries a charge of magnitude 10mu C . It is suspended by a string in a downward electric field of intensity 300N/C. If the charge on the ball is positive, then the tension in the string is (g = 10 ms^(-2))

A particle of mass m and charge Q is attached to a string of length l. It is whirled in a vertical circle in the region of an electric field E as shown in the figure-5.105.What is the speed given to the particle at the point B,so that tension in the string when the particle is at A is ten times the weight of the particle?

A point charge of 5xx10^(-6)C experiences a force of 2xx10^(-3)N when kept in a uniform electric field of intensity E. Find E.

The bob of a simple pendulum has mass 2g and a charge of 5.0muC . It is at rest in a uniform horizontal electric field of intensity 2000V//m . At equilibrium, the angle that the pendulum makes with the vertical is: (take g=10m//s^(2) )

The bob of a simple pendulum has mass 2g and a charge of 5.0muC . It is at rest in a uniform horizontal electric field of intensity 200V//m . At equilibrium, the angle that the pendulum makes with the vertical is: (take g=10m//s^(2) )