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A particle of mass 100 gm and charge 2mu...

A particle of mass 100 gm and charge `2muC` is released from a distance of 50 cm from a fixed charge of `5muC`. Find the speed of the particle when its distance from the fixed charge becomes 3 m.

Text Solution

Verified by Experts

Loss of potential energy = gain in kinetic energy
`U_(1)=U_(2)=DeltaK`
`kQq[(1)/(r_(1))-(1)/(r_(2))]=1//2mv^(2)-0`
`v=sqrt((2kQq)/(m)[(r_(2)-r_(1))/(r_(1)r_(2))])=sqrt((2xx9xx10^(9)xx5xx10^(-6)xx2xx10^(-6)xx2.5)/(0.1xx3xx0.5))=sqrt(3)m//s`
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