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A step index fibre has a relative refrac...

A step index fibre has a relative refractive index of `0.88%` what is the critical angle at the corecladding interface `(sin84^(@)24'=0.9912)`

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(i) Here `mu_(1)=1.50,mu_(2)=1.47`, `mu_(0)=1`, Critical angle `theta_(c)` at the core - cladding interface is given by, `theta_(c)= sin ^(-1)((1.47)/(1.50))=78.5^(0)`(ii) Here `mu_(1)=1.50,mu_(2)=1.47`, `mu_(0)=1`,Numerical Aperture, NA =`(mu_(1)^(2)-mu_(2)^(2))^((1)/(2))` =`[(1.50)^(2)-(1.47)^(2)]^((1)/(2))=(2.25-2.16)^((1)/(2))=0.30`(iii) Here `mu_(1)=1.50,mu_(2)=1.47`, `mu_(0)=1`, Acceptance angle `theta_(a) =sin^(-1)(NA)`, =`sin^(-1) (0.30) =17.4^(0)`(iii) Here `mu_(1)=1.50,mu_(2)=1.47`, `mu_(0)=1`, Acceptance angle `theta_(a) =sin^(-1)(NA)`, =`sin^(-1) (0.30) =17.4^(0)`
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