Home
Class 12
PHYSICS
T.V. tower has a height of 70 m. How muc...

T.V. tower has a height of 70 m. How much population is covered by the TV broadcast average population density around the tower is `1000 km^(-2)` Radius of the earth is `6. 4 xx10 ^(6)`m.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of how much population is covered by the TV broadcast from a tower of height 70 m, we will follow these steps: ### Step 1: Understand the problem We need to find the area covered by the TV broadcast and then calculate the population based on the given population density. ### Step 2: Calculate the effective radius of coverage The effective radius (d) of the broadcast can be calculated using the Pythagorean theorem. The formula for the distance to the horizon from a height \( h \) above the Earth's surface is given by: \[ d = \sqrt{(R + h)^2 - R^2} \] where \( R \) is the radius of the Earth and \( h \) is the height of the tower. ### Step 3: Substitute the values Given: - Height of the tower, \( h = 70 \) m - Radius of the Earth, \( R = 6.4 \times 10^6 \) m Substituting these values into the formula: \[ d = \sqrt{(6.4 \times 10^6 + 70)^2 - (6.4 \times 10^6)^2} \] ### Step 4: Simplify the expression Since \( h \) is very small compared to \( R \), we can use the approximation: \[ d \approx \sqrt{2Rh} \] Substituting the values: \[ d \approx \sqrt{2 \times (6.4 \times 10^6) \times 70} \] ### Step 5: Calculate the distance Calculating the above expression: \[ d \approx \sqrt{2 \times 6.4 \times 70 \times 10^6} = \sqrt{896000000} \approx 2993.33 \text{ m} \] ### Step 6: Calculate the area of coverage The area \( A \) covered by the broadcast is given by the formula: \[ A = \pi d^2 \] Substituting the value of \( d \): \[ A \approx \pi (2993.33)^2 \] ### Step 7: Calculate the area Calculating the area: \[ A \approx 3.14 \times (2993.33)^2 \approx 3.14 \times 8960000 \approx 28160000 \text{ m}^2 \] ### Step 8: Convert area to km² To convert from m² to km²: \[ A \approx \frac{28160000}{1000000} \approx 28.16 \text{ km}^2 \] ### Step 9: Calculate the population covered Given the population density is \( 1000 \text{ people/km}^2 \): \[ \text{Population} = \text{Area} \times \text{Population Density} \] \[ \text{Population} = 28.16 \times 1000 \approx 28160 \text{ people} \] ### Final Answer The population covered by the TV broadcast is approximately **28160 people**. ---
Promotional Banner

Similar Questions

Explore conceptually related problems

A TV tower has a height of 100m. How much population is covered by TV broadcast. If the average population density around the tower is 1000 km^(-2) ? (radius of earth = 6.4xx10^(6)m )

A T.V. tower has a height of 100m. How much population is covered by the T.V. broadcast if the average population density around the tower is 1000 per sq.km.Radius of the earth 6.37xx10^(6)m .By how much height of the tower be increased to double to its coverage range?

A TV broadcasting tower has a height of 100 m. How much population is covered by the TV Broadcast. If average population density around the tower is 1500 km^(-2) ? Radius of earth =6.37xx10^6 m

T.V. transmission tower at a particular station has a height of 160 m. How much population is covered by transmission, if the average population density around the tower is 1200 per km?

TV transmission tower at Kota has a height of 80 m. Radius of earth is 6400 km (i) What is its coverage range (ii) How much population is covered by transmission if the average population density around the tower is 2000 km^(-2) ?

A T.V. transmission tower at a particular station has a height of 160 m . (a) What is its coverage range ? (b) How much population is covered by transmission , if the average population density around the tower is 1200 km^(-2) ? ( c ) By how much the height of tower be increased to double its coverage range ? Given radius of earth = 6400 km .

A TV tower has a height of 70 m. If the average population density around the tower is 1000 km^(-2) , the population Covered by the TV tower

A TV tower has a height of 100 m. The population density around the TV if the population covered is 60.288 lac, is

A TV tower has a height of 150 m . The area of the region covered by the TV broadcast is (Radius of earth = 6.4 xx 10^(6) m )

A TV tower has a height of 150 m . The area of the region covered by the TV broadcast is (Radius of earth = 6.4 xx 10^(6) m )