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If g(x)=max(y^(2)-xy)(0le yle1), then th...

If `g(x)=max(y^(2)-xy)(0le yle1)`, then the minimum value of g(x) (for real x) is

A

`1//4`

B

`3-sqrt8`

C

`3+sqrt8`

D

`1//2`

Text Solution

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The correct Answer is:
B
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