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Let f(x) =(x+1)^(2)-1, x ge -1 Stateme...

Let `f(x) =(x+1)^(2)-1, x ge -1`
Statement 1: The set `{x:f(x)=f^(-1)(x)}={0,-1}.`
Statement 2: `f` is a bijection,

A

Statement - 1 is True, Statement - 2 is True, Statement - 2 is a correct explanation for Statement - 7

B

Statement - 1 is True, Statement - 2 is True, Statement - 2 is NOT a correct explanation for Statement - 7

C

Statement - 1 is True, Statement - 2 is False

D

Statement - 1 is False, Statement - 2 is True

Text Solution

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The correct Answer is:
C
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