Home
Class 12
MATHS
In a DeltaABC, angleB=(pi)/(3) and angl...

In a `DeltaABC, angleB=(pi)/(3) and angleC=(pi)/(4)` let D divide BC internally in the ratio `1:3`, then ` (sin(angleBAD))/(sin(angleCAD))` is equal to :

Text Solution

Verified by Experts

The correct Answer is:
`=> (sin lt BAD)/(sin lt CAD) = 1/3 xx (sqrt2 sqrt3)/(2) = (1)/(sqrt6)`
Promotional Banner

Similar Questions

Explore conceptually related problems

In a triagnle ABC, angle B=pi/3 " and " angle C = pi/4 let D divide BC internally in the ratio 1:3 .Then (sin (angle BAD))/((Sin (angle CAD)) is equal to

In triangle A B C ,/_B=pi/3,a n d/_C=pi/4dot Let D divided B C internally in the ratio 1: 3. Then (sin/_B A D)/(sin/_C A D) equals (a) 1/(sqrt(6)) (b) 1/3 (c) 1/(sqrt(3)) (d) sqrt(2/3)

In DeltaABC , angleA=(2pi^(c))/(3) and angleB=45^(@) . Find angleC in both the systems.

In triangleABC, angleB=60^(@) and angleC = 75^(@) . If D is a point on side BC such that ("ar"(triangleABD))/("ar"(triangleACD))=1/sqrt(3) find angleBAD

sin^(-1)(cos((5pi)/4)) is equal to

int_(0)^(pi//2) sin^(4)xcos^(3)dx is equal to :

In a DeltaABC right angled at A, a line is drawn through A to meet BC at D dividing BC in 2:1 . If tan(angleADC)=3 then angleBAD is : (a) 30^(@) (b) 45^(@) (c) 60^(@) (d) 75^(@)

In a !ABC , there is a point D on the side BC such that (BD)/(DC) = 1/3 .If angleB=pi/3,angleC=pi/4 and sinangle(CAD)=lamdasinangleBAD then lamda is equal to

The value of sin^(-1)(sin'(3pi)/(5)) is "….."

The value of sin^(-1)(sin'(3pi)/(5)) is "….."