Home
Class 12
MATHS
Find the point on the axis of the parabo...

Find the point on the axis of the parabola `3y^2+4y-6x+8 =0` from where three distinct normals can be drawn.

A

`(alpha, 1), alpha gt 2`

B

`(-1, alpha) , alpha gt 2`

C

`(alpha, -1), alpha gt 1`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

The set of points on the axis of the parabola y^2 =4ax , from which three distinct normals can be drawn to theparabola y^2 = 4ax , is

The set of points on the axis of the parabola (x-1)^(2)=8(y+2) from where three distinct normals can be drawn to the parabola is the set (h,k) of points satisfying

If (h ,k) is a point on the axis of the parabola 2(x-1)^2+2(y-1)^2=(x+y+2)^2 from where three distinct normals can be drawn, then prove that h > 2.

The set of points on the axis of the parabola (x-1)^2=8(y+2) from where three distinct normals can be drawn to the parabola is the set (h ,k) of points satisfying (a)h >2 (b) h >1 (c)k >2 (d) none of these

The set of points on the axis of the parabola (y-2)^2=4(x-1/2) from which three distinct normals can be drawn to the parabola are

If (h,k) is a point on the axis of the parabola 2{(x-1)^2 + (y-1)^2} = (x+y)^2 from where three distinct normal can be drawn, then the least integral value of h is :

Axis of the parabola x^(2)-3y-6x+6 = 0 is

The set of points on the axis of the parabola y^2-4x-2y+5=0 from which all the three normals to the parabola are real , is

The set of points on the axis of the parabola y^2-4x-2y+5=0 find the slope of normal to the curve at (0,0)

Find the point where the line x+y=6 is a normal to the parabola y^2=8x .