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If the line x+y-1=(lamda)/(2)=0 passin...

If the line `x+y-1=(lamda)/(2)=0` passing through the intersection of `x-y+1=0` and `3x+y-5=0` is perpendicular to one of them, then the value of `lamda` is:

A

`x + y + y 3=0`

B

`x + y -1 =0`

C

`x - 3y - 5 =0`

D

`x + 3y + 5=0`

Text Solution

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The correct Answer is:
B
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