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Statement -1 : The equation of chord of ...

Statement -1 : The equation of chord of the circel `x ^(2) + y ^(2) - 6x + 10y - 9=0,` which is bisected at the point `(-2,4)` must be `x + y - 2=0.`
Statement -2 : In notations the equation of chord of the circle `S =0` bisected at `x _(1), y _(1)` must be `T = S_(1).`

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To solve the problem, we need to analyze both statements regarding the chord of the circle given by the equation \( x^2 + y^2 - 6x + 10y - 9 = 0 \) and the point at which the chord is bisected, which is \((-2, 4)\). ### Step 1: Rewrite the Circle Equation The given equation of the circle is: \[ x^2 + y^2 - 6x + 10y - 9 = 0 \] We can rewrite it in standard form by completing the square. 1. For \(x\): \[ x^2 - 6x = (x - 3)^2 - 9 \] 2. For \(y\): \[ y^2 + 10y = (y + 5)^2 - 25 \] Substituting these into the equation gives: \[ (x - 3)^2 - 9 + (y + 5)^2 - 25 - 9 = 0 \] Simplifying this, we have: \[ (x - 3)^2 + (y + 5)^2 - 43 = 0 \] Thus, the standard form of the circle is: \[ (x - 3)^2 + (y + 5)^2 = 43 \] This indicates that the center of the circle is \((3, -5)\) and the radius is \(\sqrt{43}\). ### Step 2: Use the Chord Bisector Formula The equation of the chord of a circle that is bisected at a point \((x_1, y_1)\) can be expressed as: \[ T = S_1 \] where \(T\) is the equation of the chord and \(S\) is the equation of the circle. 1. The equation of the circle \(S\) is: \[ S = x^2 + y^2 - 6x + 10y - 9 \] 2. For the point \((-2, 4)\), we calculate \(S_1\): \[ S_1 = (-2)^2 + (4)^2 - 6(-2) + 10(4) - 9 \] \[ = 4 + 16 + 12 + 40 - 9 = 63 \] ### Step 3: Substitute into the Chord Equation Using the point \((-2, 4)\) in the chord equation \(T\): \[ T = x(-2) + y(4) - (S_1) = 0 \] This gives: \[ -2x + 4y - 63 = 0 \] Rearranging this, we can express it as: \[ 2x - 4y + 63 = 0 \] or simplifying further, we can divide by 2: \[ x - 2y + 31.5 = 0 \] ### Step 4: Compare with the Given Statement The statement claims that the equation of the chord is \(x + y - 2 = 0\). However, our derived equation does not match this. Therefore, **Statement 1 is false**. ### Step 5: Validate Statement 2 Statement 2 states that the equation of the chord of the circle \(S = 0\) bisected at \((x_1, y_1)\) must be \(T = S_1\). This is a standard result in coordinate geometry, and we have verified it through our calculations. Thus, **Statement 2 is true**. ### Conclusion - **Statement 1**: False - **Statement 2**: True
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STATEMENT-1 : The equation of chord of circle x^(2) + y^(2) - 6x + 10y - 9 = 0 , which is be bisected at (-2, 4) must be x + y = 2. and STATEMENT-2 : The equation of chord with mid-point (x_(1), y_(1)) to the circle x^(2) + y^(2) = r^(2) is xx_(1) + yy_(1) = x_(1)^(2) + y^(2) .