The equation of line passing through `(2, 3, -1)` and perpendicular to the plane `2x + y - 5z = 12`

Equation of a line passing through (-1,2,-3) and perpendicular to the plane 2x+3y+z+5=0 is

Equations of the line passing through (1,1,1) and perpendicular to the plane 2x+3y+z+5=0 are

find the equation of a line passing through (3,-2)and perpendicular to the line x-3y+5=0

The equation of the line passing though the point (1,1,-1) and perpendicular to the plane x -2y - 3z =7 is :

The equation of the plane passing through the point (1,1,1) and perpendicular to the planes 2x+y-2z=5 and 3x-6y-2z=7

The equation of the plane passing through the point (1,1,1) and perpendicular to the planes 2x+y-2z=5 and 3x-6y-2z=7 is

Equation of plane passing through (2,3,4) and parallel to the plane x+2y+4z=5 is

Find the equation of a line, passes through (-1,2) and perependicular to the line 2x+3y=1 .

Obtain the equation of the plane passing through the point (1, -3, -2) and perpendicular to the planes x+2y+2z=5\ a n d\ 3x+3y+2z=8.

The equation of the line passing through (1, 1, 1) and perpendicular to the line of intersection of the planes x+2y-4z=0 and 2x-y+2z=0 is