If radiation correction is not considered in specific heat measurement. The measured value of If radio specific heat will be

Options

A. more than its actual value.
B. less than its actual value.
C. remains same as actual value.
D. none of these.

Answer

To solve the problem regarding the measured value of specific heat when radiation correction is not considered, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Specific Heat**:
Specific heat (c) is defined as the amount of heat (Q) required to change the temperature (ΔT) of a unit mass (m) of a substance. The formula is given by:
\[ c = \frac{Q}{m \Delta T} \]

2. **Considering Radiation Correction**:
In a real-world scenario, when measuring specific heat, heat loss due to radiation can occur. If we do not account for this radiation loss, the heat measured (Q) will be higher than the actual heat absorbed by the substance.

3. **Effect on Measured Temperature Change**:
If radiation losses are not considered, the temperature change (ΔT) observed will be greater than it would be if radiation were accounted for. This is because the heat that should have been lost to radiation is instead contributing to the temperature change.

4. **Resulting Calculation**:
If we denote the actual specific heat as \( c_{actual} \) and the measured specific heat as \( c_{measured} \), we can express this relationship as:
\[ c_{measured} = \frac{Q_{measured}}{m \Delta T_{measured}} \]
Since \( Q_{measured} > Q_{actual} \) and \( \Delta T_{measured} > \Delta T_{actual} \), it follows that:
\[ c_{measured} > c_{actual} \]

5. **Conclusion**:
Therefore, if radiation correction is not considered in specific heat measurement, the measured value of specific heat will be more than its actual value.

### Final Answer:
The measured value of specific heat will be **more than its actual value**.