Home
Class 12
PHYSICS
How much energy must a bomberding proton...

How much energy must a bomberding proton possess to cause the reaction `._(3)Li^(7) + ._(1)H^(1) rarr ._(4)Be^(7) + ._(0)n^(1)`
(Mass of `._(3)Li^(7)` atom is `7.01400`, mass of `._(1)m^(1)` atom is `1.0783` , mass of `._(4)Be^(7)` atom is `7.01693`)

Text Solution

Verified by Experts

Since the mass of an atom include the masses of the atomic electrons,the appropriate number of electron masses must be substracted from the given values.Total `8.02383-4m_(e)`, `8.02559-4m_(e)`, Mass defect =8.02383-8.02559=-0.00176.The Q-value of the reaction ,`Q==0.00176 mu=-1.65MeV`.The energy is supplied as the KE of the bombarding proton. The incident proton must have more than this energy because the system must possess some KE even after the reaction,so that momentum is conserved.With momentum conservation taken into account,the minimum KE that the incident particle must have can be found with the formula.`E_(th)=-(1+(m)/(M))Q=-(1+(1)/(7))(-1.65)=1.89MeV`.
Promotional Banner

Similar Questions

Explore conceptually related problems

Calculate the loss in mass during the change: ._(3)Li^(7) + ._(1)He^(1) rarr 2 ._(2)He^(4) + 17.25 MeV

Balance the following nuclear reactions: a. ._(3)Li^(7) + ._(0)n^(1) rarr 2 ._(2)He^(4) + ? b. ._(42)Mo^(94) + ._(1)H^(2) rarr ._(0)n^(1) + ?

._(7)N^(14)+ ._(0)n^(1)rarr ...................+._(1)H^(1)

Which one of the following nuclear transformation is (np) type? a. ._(3)Li^(7) + ._(1)H^(1) rarr ._(4)Be^(7) + ._(0)n^(1) b. ._(33)As^(75) + ._(5)He^(4) rarr ._(35)Bi^(78) + ._(0)n^(1) c. ._(83)Bi^(209) + ._(1)H^(2) rarr ._(84)Po^(210) + ._(0)n^(1) d. ._(21)Sc^(45) + ._(0)n^(1) rarr ._(20)Ca^(45) + ._(1)H^(1)

Calculate the binding energy for ._(1)H^(2) atom. The mass of ._(1)H^(2) atom is 2.014102 amu where 1n and 1p have their weights 2.016490 amu. Neglect mass of electron.

._(7)^(7)Li + _(1)^(1)P rarr X , Identify X if reaction is (p,alpha) type.

Sum to n terms of the series (1)/(1.4.7) + (1)/(4.7.10) + (1)/(7.10.13) +…….

If the binding energy per nucleon in ._(3)Li^(7) and ._(2)He^(4) nuclei are respectively 5.60 MeV and 7.06 MeV, then the ebergy of proton in the reaction ._(3)Li^(7) +p rarr 2 ._(2)He^(4) is

Determine the product of the reaction: ._3^7Li +._2^4He rarr ? +n What is the Q value of the reaction?

Bombardment of lithium with protons gives rise to the following reaction : ._3Li^7 + ._1H^1 to 2 (._2He^4)+Q . Find the Q-value of the reaction. The atomic masses of lithium, proton and helium are 7.016 u, 1.008 u and 4.004 u respectively.