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Find the maximum kinetic enegry of photo...

Find the maximum kinetic enegry of photoelectrons liberated form the surface of lithium by electromagnetic radiation whose electric component varies with time as `E = a(1+cos omegat) cos omega_(0)t`, where `a` is a constant, `omega = 6.10^(14)s^(-1)` and `omega_(0) = 360.10^(15)s^(-1)`.(Work function of Lithiuim = 2.39eV)

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To find the maximum kinetic energy of photoelectrons liberated from the surface of lithium by the given electromagnetic radiation, we will follow these steps: ### Step 1: Understand the Electric Field Equation The electric component of the electromagnetic radiation is given as: \[ E(t) = a(1 + \cos(\omega t)) \cos(\omega_0 t) \] This can be simplified using trigonometric identities. ### Step 2: Simplify the Electric Field ...
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