Home
Class 12
PHYSICS
The de-Broglie’s wavelength of electron ...

The de-Broglie’s wavelength of electron present in first Bohr orbit of ‘H’ atom is :

A

Radius of the orbit

B

Perimeter of the orbit

C

Diameter of the orbit

D

Half of the perimeter of the orbit

Text Solution

Verified by Experts

The correct Answer is:
B
The de -Broglie wavlength ` lambda =(h)/(mv)`……(1), where the linear momentum of an orbiting eclectron is given as `mvr=(nh)/(2pi)` for first orbit n=1, `implies mv= (h)/(2pir)`…..(2), using (1) and (2) we obtain `lambda=(h)/(((h)/(2pir)))=2pir`=perimeter of the orbit.
Promotional Banner

Similar Questions

Explore conceptually related problems

The de-Broglie wavelength of an electron in the first Bohr orbit is

The de Broglie wavelength of an electron in the 3rd Bohr orbit is

The de-Broglie wavelength of an electron moving in the nth Bohr orbit of radius ris given by

If the de-Broglie wavelength of an electron revolving in 2^"nd" orbit of H-atom is x, then radius of that orbit is given by :

The de Broglie wavelength of an electron in the nth Bohr orbit is related to the radius R of the orbit as:

If the de Broglie wavelength of the electron in n^(th) Bohr orbit in a hydrogenic atom is equal to 1.5pia_(0)(a_(0) is bohr radius), then the value of n//z is :

If a_(0) be the radius of first Bohr's orbit of H-atom, the de-Broglie's wavelength of an electron revolving in the second Bohr's orbit will be:

what is the ratio of de-Broglie wavelength of electron in the second and third Bohr orbits in the hydrogen atoms?

Calculate the velocity of an electron in the first Borh's orbit of hydrogen atom (given r = a_(0)) b. Find de Broglie wavelength of the electron in the first Bohr's orbit c. Find the orbital angular momentum of 2p orbital in terms of h//2pi units

The de-Broglie wavelength of electron in a certain orbit 'n' of Be^"3+" ion is found to be 5.83 Å.Find the value of 'n'.Take I^"st" Bohr radius for H-atom =53 pm :