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The ratio of molecules mass of two radia...

The ratio of molecules mass of two radiactive substances is `(3)/(2)` and the ratio of their decay constant is `(4)/(3)` Then the ratio of their intial activity per mol will be

Text Solution

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Activity `R = lambdaN`
Number of nuclei (N) per mole are equal for both the substances
`therefore`   `Rproplambda` 
Or `(R_(1))/(R_(2))=(lambda_(1))/(lambda_(2))=(4)/(3)`
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