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Half-life of a radioactive sunstance A i...

Half-life of a radioactive sunstance A is two times the half-life of another radioactive substance B Intilally the number of nuclie of A and B are `N_(A)` and `N_(B)` respectively After three half lives of A number of nuclie of bothe equal. Then the ratio `N_(A)//N_(B)` is

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Let number of c-decays are x and number of `beta`-decays are y. Then
92 - 2x + y = 85
or, 2x - y = 7  .. (1)
and 238 - 4x = 210
X = 7 Substituting this value in equation (1), we get y=7
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