One milliwatt of light of wavelength lam...

One milliwatt of light of wavelength `lambda=4560Å` is incident on a cesium metal surface. Calculate the electron current liberated. Assume a quantum efficiency of `eta=0.5 %` [ work functions for cesium `=1.89 eV`] Take `hc=12400 eV-Å`

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The correct Answer is:

`84 xx 10^(-6) Amp`

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One milliwatt of light of wavelength `lambda=4560Å` is incident on a cesium metal surface. Calculate the electron current liberated. Assume a quantum efficiency of `eta=0.5 %` [ work functions for cesium `=1.89 eV`] Take `hc=12400 eV-Å`

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