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An alpha particle and a proton have thei...

An `alpha` particle and a proton have their masses in the ratio 4:1 and charges in the ratio 2: 1. Find ratio of their de-Broglie wavelengths when both move with equal velocities.

A

`2:1`

B

`1:1`

C

`4:1`

D

`1:4`

Text Solution

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The correct Answer is:
To find the ratio of the de-Broglie wavelengths of an alpha particle and a proton when both move with equal velocities, we can follow these steps: ### Step 1: Understand the de-Broglie wavelength formula The de-Broglie wavelength (λ) is given by the formula: \[ \lambda = \frac{h}{mv} \] where \( h \) is Planck's constant, \( m \) is the mass of the particle, and \( v \) is its velocity. ### Step 2: Define the variables for the alpha particle and proton Let: - For the alpha particle (particle 1): - Mass = \( m_1 \) - Velocity = \( v_1 \) - de-Broglie wavelength = \( \lambda_1 \) - For the proton (particle 2): - Mass = \( m_2 \) - Velocity = \( v_2 \) - de-Broglie wavelength = \( \lambda_2 \) ### Step 3: Write the expressions for the de-Broglie wavelengths Using the formula for de-Broglie wavelength: \[ \lambda_1 = \frac{h}{m_1 v_1} \] \[ \lambda_2 = \frac{h}{m_2 v_2} \] ### Step 4: Find the ratio of the de-Broglie wavelengths The ratio of the de-Broglie wavelengths is: \[ \frac{\lambda_1}{\lambda_2} = \frac{h/m_1 v_1}{h/m_2 v_2} = \frac{m_2 v_2}{m_1 v_1} \] Since both particles are moving with equal velocities, we have \( v_1 = v_2 \). Thus, we can simplify the ratio: \[ \frac{\lambda_1}{\lambda_2} = \frac{m_2}{m_1} \] ### Step 5: Use the given mass ratio According to the problem, the mass ratio of the alpha particle to the proton is given as: \[ \frac{m_1}{m_2} = \frac{4}{1} \] This means: \[ m_1 = 4m_2 \] Thus, we can write: \[ \frac{m_2}{m_1} = \frac{1}{4} \] ### Step 6: Conclude the ratio of the de-Broglie wavelengths Substituting this into the ratio of the de-Broglie wavelengths: \[ \frac{\lambda_1}{\lambda_2} = \frac{m_2}{m_1} = \frac{1}{4} \] ### Final Result Therefore, the ratio of the de-Broglie wavelengths of the alpha particle to the proton is: \[ \lambda_1 : \lambda_2 = 1 : 4 \]
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