Home
Class 12
PHYSICS
""^(238)U(IIIB) changes to ""^(234)Th by...

`""^(238)U(IIIB)` changes to `""^(234)Th` by emission of `alpha`-particle. Daughter element will be in
(1) IIIB (2) IB (3) VB (4) HA

A

`alpha`-particle of kinetic energy 5.137 MeV

B

`alpha`-particle of kinetic energy 5.421 MeV

C

`alpha`- particle of kinetic energy 5.371 MeV

D

`alpha`-particle of kinetic energy 5.172 MeV

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

""_(92)^(238) U(IIIB) changes to ""_(9)^(234) Th by emission of alpha - particle . Daughter element will be in -

._(90)Th^(232) belongs to III group. It items an alpha -particle. The daughter element belongs to a. I group b. II group III. Group d. IV group

1 mg of Th emits 22 alpha -particles per unit solid angle per minute. Calculate t_(1//2) or Th (Th = 232) .

The emission of an alpha- particle reduces the mass of nuclei by 4 units and increases its atomic number by 2.

._(92)^(238)U has 92 protons and 238 nucleons. It decays by emitting an alpha particle and becomes:

In the disintegration of a radioactive element, alpha - and beta -particles are evolved from the nucleus. ._(0)n^(1) rarr ._(1)H^(1) + ._(-1)e^(0) + Antineutrino + Energy 4 ._(1)H^(1) rarr ._(2)He^(4) + 2 ._(+1)e^(0) + Energy Then, emission of these particles changes the nuclear configuration and results into a daughter nuclide. Emission of an alpha -particles results into a daughter element having atomic number lowered by 2 and mass number by 4, on the other hand, emission of a beta -particle yields an element having atomic number raised by 1. How many alpha - and beta -particle should be emitted from a radioactive nuclide so that an isobar is formed?

In the disintegration of a radioactive element, alpha - and beta -particles are evolved from the nucleus. ._(0)n^(1) rarr ._(1)H^(1) + ._(-1)e^(0) + Antineutrino + Energy 4 ._(1)H^(1) rarr ._(2)He^(4) + 2 ._(+1)e^(0) + Energy Then, emission of these particles changes the nuclear configuration and results into a daughter nuclide. Emission of an alpha -particles results into a daughter element having atomic number lowered by 2 and mass number by 4, on the other hand, emission of a beta -particle yields an element having atomic number raised by 1. Which of the following combinations give finally an isotope of the parent element?

In the disintegration of a radioactive element, alpha - and beta -particles are evolved from the nucleus. ._(0)n^(1) rarr ._(1)H^(1) + ._(-1)e^(0) + Antineutrino + Energy 4 ._(1)H^(1) rarr ._(2)He^(4) + 2 ._(+1)e^(0) + Energy Then, emission of these particles changes the nuclear configuration and results into a daughter nuclide. Emission of an alpha -particles results into a daughter element having atomic number lowered by 2 and mass number by 4, on the other hand, emission of a beta -particle yields an element having atomic number raised by 1. During beta -decay, the mass of atomic nucleus

In the disintegration of a radioactive element, alpha - and beta -particles are evolved from the nucleus. ._(0)n^(1) rarr ._(1)H^(1) + ._(-1)e^(0) + Antineutrino + Energy 4 ._(1)H^(1) rarr ._(2)He^(4) + 2 ._(+1)e^(0) + Energy Then, emission of these particles changes the nuclear configuration and results into a daughter nuclide. Emission of an alpha -particles results into a daughter element having atomic number lowered by 2 and mass number by 4, on the other hand, emission of a beta -particle yields an element having atomic number raised by 1. A radioactive element belongs to III B group, it emits ona alpha - and beta -particle to form a daughter nuclide. The position of daughter nuclide will be in

How many alpha and beta -particles are emitted in the transformation ""_(92)^(238)U rarr ""_(92)^(234)U