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A body is dropped from a height h=50 m. ...

A body is dropped from a height h=50 m. Another body is projected vertically up with a speed V=10 m//sec after a time `t_0`= 2 sec from the instant of release of the first body. Find the time of their meetings.

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To solve the problem, we need to analyze the motion of both bodies separately and then find the time at which they meet. ### Step 1: Define the motion of the first body The first body is dropped from a height of \( h = 50 \, \text{m} \). Since it is dropped, its initial velocity \( u_1 = 0 \). The distance fallen by the first body after time \( t \) is given by the equation of motion: \[ S_1 = u_1 t + \frac{1}{2} g t^2 \] Substituting \( u_1 = 0 \): ...
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