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Acceleration of a particle which is at r...

Acceleration of a particle which is at rest at `x=0` is `a=(4-2x)hati`. Select the correct alternative (s)

A

particle further comes to rest x=4

B

particle oscillates about x=2

C

maximum speed of the particle is 4 units

D

all of the above

Text Solution

Verified by Experts

The correct Answer is:
a,b

`v(dv)/(dx)=(4-2x)=int_(O)^(V)vdv=int_(O)^(X)(4-2x)dx`
`impliesv^(2)=4x-x^(2)`
`v^(2)=8x-2x^(2)`
`V^(2)=O` and x-0 and x=4
next `2v(dv)/(dt)=8v-4vx`
a=4-2x
`implies`0=4-2x since a=0 at any points
x=4 thus it will oscillates about it.
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