Home
Class 12
PHYSICS
For the previous question, the accelerat...

For the previous question, the acceleration of the particle at any time `t` is :

Text Solution

Verified by Experts

Time of swimming , `t=(d)/(v_(mw)costheta)`
`rArr t=(1//2)/(5cos30^(2))=(1)/(10)xx(2)/(sqrt3)=(1)/(5sqrt3)hr`
Promotional Banner

Similar Questions

Explore conceptually related problems

The velovity-time graph of a particle moving in a straitht line is shown in . The acceleration of the particle at t=9 s is. .

The x and y coordinates of the particle at any time are x=5t-2t^(2) and y=10t respectively, where x and y are in meters and t in seconds. The acceleration of the particle at t=2s is:

The x and y coordinates of the particle at any time are x=5t-2t^(2) and y=10t respectively, where x and y are in meters and t in seconds. The acceleration of the particle at t=2s is:

The x and y coordinates of the particle at any time are x = 5t - 2t^(2) and y = 10t respectively, where x and y are in meters and t in seconds. The acceleration of the particle at I = 2s is

The x and y coordinates of a particle at any time t are given by x = 2t + 4t^2 and y = 5t , where x and y are in metre and t in second. The acceleration of the particle at t = 5 s is

In simple harmonic motion, the ratio of acceleration of the particle to its displacement at any time is a measure of

In the previous question,if the particle has -Q charge the time spend by the particle in the field will be .

the angular velocity omega of a particle varies with time t as omega = 5t^2 + 25 rad/s . the angular acceleration of the particle at t=1 s is

For a particle moving in a straight line, the displacement of the particle at time t is given by S=t^(3)-6t^(2) +3t+7 What is the velocity of the particle when its acceleration is zero?