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A body moves in a circular path of the r...

A body moves in a circular path of the radius R with deceleration so that at any moment of time its tangential and normal acceleration are equal in magnitude. At the initial moment `t = 0`, the velocity of the body is `v_(0)` then the velocity of the body after it has moved S at any time will be

Text Solution

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The correct Answer is:
`v=(v_(0))/(1+(V_(0))/(R)t);v=v_(0)e^(-S//R)`
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