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A ballon starts rising from the surface ...

A ballon starts rising from the surface of earth ,the ascension rate is constant and is equal to v0. Due to wind the balloon gathers the horizontal velocity component vx =ay, where a is a positive constant and y is the height of ascent . Find
(i) The horizontal drift of the balloon x(y).
(ii) THe total , tangential and normal accelerations of the balloon.

Text Solution

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The correct Answer is:
(a) `x=((a)/(2v_(0)))y^(2)` (b) `f_("total")=av_(0).f_("langetial")=(a^(2)v_(0)y)/(sqrt(v_(o)^(2)+a^(2)y^(2))),f_("normal")=(av_(o)^(2))/(sqrt(v_(o)^(2)+a^(2)y^(2)))`
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