A block of mass m is moving down with constant velocity along an inclined plane of inclination `theta`. What is the work done by external force in pulling the block along the inclined plane through a height h with constant velocity?

Explanation

To solve the problem, we need to find the work done by an external force in pulling a block of mass \( m \) along an inclined plane through a height \( h \) with constant velocity. Here is a step-by-step solution:

### Step 1: Understand the Forces Acting on the Block
- The block of mass \( m \) is moving down the inclined plane with a constant velocity, which means the net force acting on it is zero.
- The gravitational force acting on the block is \( mg \), where \( g \) is the acceleration due to gravity.
- The gravitational force can be resolved into two components:
- Parallel to the incline: \( mg \sin \theta \)
- Perpendicular to the incline: \( mg \cos \theta \)
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